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On the first of each month, Sasha runs a 5k race. She keeps track of her times to track her progress. Her time in minutes is recorded in the table:


Jan 39.55 July 34.38
Feb 40.51 Aug 36.48
Mar 41.01 Sept 39.87
Apr 37.76 Oct 50.32
May 35.32 Nov 40.59
June 33.28 Dec 41.71


Determine the difference between the mean of the data, including the outlier and excluding the outlier. Round to the hundredths place.
38.98
38.22
1.21
1.01

Respuesta :

bayenmilligan

Answer:

1.01

Step-by-step explanation:

Mean with outliner = (39.55 + 40.51 + 41.01 + 37.76+ 35.32 + 33.28 + 34.38 + 36.48 + 39.87 + 50.32 + 40.59 + 41.71)/12 = 39.23 seconds.

In this case, the outlier comes to be the data: 50.32. If we don't consider that data point, the mean equals:

Mean wihout outliner = (39.55 + 40.51 + 41.01 + 37.76+ 35.32 + 33.28 + 34.38 + 36.48 + 39.87 + 40.59 + 41.71)/11 = 38.22

The difference is:  39.23 - 38.22 = 1.01