Haley's function in standard form is [tex]6x^2-10x-2=0[/tex]
The standard quadratic equation is expressed as:
[tex]ax^2+bx+c=0[/tex]
The general solution to the system of equation is given as:
[tex]x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]
Comparing with the given formula, we will see that:
a = 7
b = -10
c = -2
Substitute into the general quadratic equation to have:
[tex]6x^2-10x-2=0[/tex]
Hence Haley's function in standard form is [tex]6x^2-10x-2=0[/tex]
Learn more on quadratic equation here: https://brainly.com/question/1214333
