What is the range of the function f(x) = –2(6x) + 3? (negative infinity, negative 2 Right-bracket (negative infinity, 3) Left-bracket negative 2, infinity) Left-bracket 3, infinity)

Respuesta :

Answer:

B

(negative infinity, 3)

Step-by-step explanation:

Using exponential function concepts, it is found that the range of the function [tex]f(x) = -2(6)^x + 3[/tex] is given by:

[tex](-\infty, 3)[/tex]

What is an exponential function?

An exponential function is modeled by:

[tex]y = ab^x + c[/tex]

In which:

  • a is the initial value.
  • b is the rate of change.
  • c is the vertical shift.

As for the range, we have that:

  • If a > 0, the range is [tex](c, \infty)[/tex].
  • If a < 0, the range is [tex](-\infty, c)[/tex].

In this problem, the function is given by:

[tex]f(x) = -2(6)^x + 3[/tex].

Hence the coefficients are a = -2 < 0, b = 6 and c = 3, and the range is given by:

[tex](-\infty, 3)[/tex]

More can be learned about exponential function concepts at https://brainly.com/question/25537936