Respuesta :

aabdulsamir

Answer:

Heat lost would be 606.375J

Explanation:

Mass = 63.0g

T1 = 48°C

T2 = 23°C

Specific heat capacity of copper (c) = 0.385J/g°C

Q = Mc∇T

Q = Mc(T₂ - T₁)

Q = 63 * 0.385 * (23 - 48)

Q = 24.255 * -25

Q = -606.375J

The heat lost would be 606.375J

xero099

Answer:

623 J

Explanation:

The quantity of heat released by the sample is quantified with the help of the First Law of Thermodynamics:

[tex]Q = (63\,g)\cdot \left(0.390\,\frac{J}{g\cdot ^{\circ}C} \right)\cdot (23^{\circ}C-48^{\circ}C)[/tex]

[tex]Q = -614.25\,J[/tex]

The best approximation is 623 J.