Answer:
In a nutshell, the pressure does not change.
Explanation:
Let assume that amount of moles is conserved, then following relationship is constructed from the Equation of State for Ideal Gas:
[tex]\frac{P_{o}\cdot V_{o}}{T_{o}} = \frac{P_{f}\cdot V_{f}}{T_{f}}[/tex]
The final pressure is now cleared in the equation:
[tex]P_{f} = \left(\frac{V_{o}}{V_{f}} \right)\cdot \left(\frac{T_{f}}{T_{o}} \right) \cdot P_{o}[/tex]
[tex]P_{f} = \left(\frac{1}{2} \right)\cdot (2) \cdot P_{o}[/tex]
[tex]P_{f} = P_{o}[/tex]
In a nutshell, the pressure does not change.
