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How much heat is required, in calories, to raise the temperature of 57.8 grams of silver from 17.0 C to 43.5 C, if the specific heat of silver = 0.057 cal/gC ?

Respuesta :

aabdulsamir

Answer:

Q = 87.31cal

Explanation:

Mass = 57.8g

T1 = 17.0°C

T2 = 43.5°C

Specific heat capacity (c) = 0.057cal/g°C

Q = MC∇T

Q = M*C*(T₂ - T₁)

Q = 57.8 * 0.057 * (43.5 - 17.0)

Q = 3.2946 * 26.5

Q = 87.306 cal

Q = 87.31cal

xero099

Answer:

[tex]Q = 87.307\,cal[/tex]

Explanation:

The heat required to raise temperature is determined with the help of the First Law of Thermodynamics:

[tex]Q = m\cdot c \cdot \Delta T[/tex]

[tex]Q = (57.8\,g)\cdot \left(0.057\,\frac{cal}{g\cdot ^{\circ}C} \right)\cdot (43.5^{\circ}C-17^{\circ}C)[/tex]

[tex]Q = 87.307\,cal[/tex]

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