Respuesta :
Answer:
[tex] z = 1.83[/tex]
And the p value calculated for the right tailed ted is:
[tex] p_v = 0.033[/tex]
The significance level provided for this case is 5% or [tex]\alpha=0.05[/tex]. We can see that the p value is lower than this significance level so then we have enough evidence to reject the null hypothesis in favor to the alternative hypothesis and we can conclude that the true parameter of interest for this case is significantly higher than 16. If we find a confidence interval at the same significance level we should get the same results.
Explanation:
for this case she want to test the following system of hypothesis.
Null hypothesis: [tex]p =16[/tex]
Alternative hypothesis: [tex]p>16[/tex]
And the statistic for this case is given by:
[tex] z = 1.83[/tex]
And the p value calculated for the right tailed ted is:
[tex] p_v = 0.033[/tex]
The significance level provided for this case is 5% or [tex]\alpha=0.05[/tex]. We can see that the p value is lower than this significance level so then we have enough evidence to reject the null hypothesis in favor to the alternative hypothesis and we can conclude that the true parameter of interest for this case is significantly higher than 16. If we find a confidence interval at the same significance level we should get the same results.
It can be deduced that the results of the significance test don't agree with the results of Clarke’s confidence interval.
What is a significance test?
It can be inferred that a significant test simply means a formal procedure that's used for comparing observed data with a hypothesis.
In this case, the p value is lower than the significance level. Hence, the results of the significance test don't agree with the results of Clarke’s confidence interval.
Learn more about test of significance on:
https://brainly.com/question/4599596
