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A sum of money is invested at 12% compounded quarterly. About how long will it take for the amount of money to double?
Compound interest formula: V(t)=P(1+ r/n)^nt
t = years since initial deposit
n = number of times compounded per year
r = annual interest rate (as a decimal)
P = initial (principal) investment V(t) = value of investment after t years
A. 5.9 years
B. 6.1 years
C. 23.4 years
D. 24.5 years

Respuesta :

Answer:Follow the given formula.  The initial amount of money invested, P, becomes 2P (same thing as "doubles) after t years.  Since compounding is quarterly, n=4.  The annual interest rate is 12%.  That is, r=0.12.

Then we have 2P = P (1 + 0.12/4)^(4t) and need only solve for time, t.

Simplifying the above equation:  2 = (1.03)^(4t)

We must isolate 4t, and then isolate t.  To do this, take the common log of both sides of the above equation.  We get:

log 2 = (4t) log 1.03.  This gives us 4t = [log 2] / [log 1.03], or

4t =  23.4498

Dividing both sides by 4, we get     t = 5.86 (years).

Step-by-step explanation: Mark me as brainliest

Answer:

5.9 Years

Step-by-step explanation:

correct on edge