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The vertex of the graph of a quadratic function is (3, 1) and the y-intercept is (0, 10). Which of the following is the
equation of the function?
A y = 2x2 - 12x +10
1.2.2. 11
--x + 3x - -
B.
2
C. y=x2 - 6x +10
D. y = 2x2 – 7x+4

Respuesta :

kathrinep

Answer:

C. y = x² - 6x + 10

Step-by-step explanation:

Formula f(x)=a(x-h)^2+k (h,k) is vertex

Y=a (x-3)^2+1

Plug in y intercept

10=a (0-3)2+1

10=-3^2a+1

10=9a+1

9=9a

A=1

Y=(x-3)2 +1

Y=x2-6x+9+1

Y=x2-6x+10

https://brainly.com/question/3584775#citedsource

kathrinepalmer

Answer:

C. y = x² - 6x + 10

Step-by-step explanation:

Formula f(x)=a(x-h)²+k (h,k) is vertex

Y=a (x-3)²+1

Plug in y intercept

10=a (0-3)²+1

10=-3²ᵃ+1

10=9a+1

9=9a

a=1

Y=(x-3)² +1

Y=x²-6x+9+1

Y=x²-6x+10

https://brainly.com/question/3584775#citedsource

https://brainly.com/question/16336809#citedsource

Brainliest Please!!!!!!!!!!

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