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In order to estimate the mean amount of time computer users spend on the internet each​ month, how many computer users must be surveyed in order to be 9595​% confident that your sample mean is within 1010 minutes of the population​ mean? Assume that the standard deviation of the population of monthly time spent on the internet is 221221 min. What is a major obstacle to getting a good estimate of the population​ mean? Use technology to find the estimated minimum required sample size.

Respuesta :

jmonterrozar

Answer:

1877 computer users

Step-by-step explanation:

We have that for 95% of confident, the value of z has a value of 1.96 (attached table about it), they also mention the margin of error (E) that is 10 and finally the standard deviation (sd) that has a value of 221.

We apply the following formula:

n = [z * sd / E] ^ 2

replacing:

n = [1.96 * 221/10] ^ 2

n = 1876.27

that is, the minimum sample size is 1877

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