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A password must have one letter and two digits. How many different passwords are possible? Hint: 26 letters in the alphabet and 10 possible digits

Respuesta :

Answer:

7020.

Step-by-step explanation:

The letter could be any 1 of the 26 and it could be placed in any 1 of 3 places so this makes 26*3 = 78 possibilities.

For each of these  there is any one of  permutations of 2 digits from 10

= 10P2 = 10! / 8! = 10*9 = 90.

So the answer is 78 * 90 =  7020.

Note I am assuming that the 2 digits picked are different - no duplicates.