WHOEVER ANSWERS THIS I WILL MARK AS BRAINLIEST PLEASE HELP A bottle of sugar syrup soda had 4 ⅓ grams of sugar in it. If Tom drank 3 full bottles and 7/9 of a bottle, how many grams of sugar did he drink?

Respuesta :

Answer:

Its 16 and [tex]\frac{10}{27}[/tex]

Step-by-step explanation:

do [tex]\frac{13}{3}*\frac{34}{9}[/tex] to get [tex]16 \frac {10}{27}[/tex]

Answer:

[tex]16\frac{10}{27} \mbox{g}[/tex]

Step-by-step explanation:

This is essentially a multiplication problem! We have

[tex]4\frac{1}{3} \mbox{g sugar/bottle} \times3\frac{7}{9} \mbox{ bottles}[/tex]

Let's start by figuring out the number of grams in 3 bottles. If one bottle has 4 1/3 g of sugar, 3 bottlesshould have 4 × 3 = 12g plus another 1/3 × 3 = 1g, for a total of 12 + 1 = 13g. Taking 7/9 of 4 1/3g, we have

[tex]4\frac{1}{3} \times\frac{7}{9}=\frac{13}{3}\times\frac{7}{9} =\frac{91}{27}=3\frac{10}{27}\mbox{g}[/tex]

Adding that to the 13g from the 3 bottles gives us a total of 13 + 3 10/27 = [tex]16\frac{10}{27} \mbox{g}[/tex]