Answer:
2.64*10^-18 N
Explanation:
You have the following vectors:
[tex]\vec{v}=5.00\hat{i}-6.00\hat{j}+1.00\hat{k}\\\\\vec{B}=1.00\hat{i}+2.00\hat{j}-1.00\hat{k}[/tex]
The magnitude of the magnetic force is given by the following equation:
[tex]|\vec{F_B}|=q|\vec{v}\ X\ \vec{B}|[/tex]
Thus, you calculate the cross product between v and B (for example with the determinant method) and you obtain:
[tex]\vec{v}\ X\ \vec{B}=4\hat{i}-\hat{j}+16\hat{k}[/tex]
Finally the magnitude of the force will be:
[tex]|\vec{F_B}|=(1.6*10^{-19}C)\sqrt{(4)^2+(-1)^2+(16)^2}N=2.64*10^{-18}N[/tex]
then, the magnetic force is 2.64*10^-18 N
