Answer:
B) 10.1 L
Explanation:
Hello,
In this case, for the given chemical reaction which should be corrected as shown below:
[tex]CaCO_3 + HCl \rightarrow CaCl_2 + H_2O +CO_2[/tex]
Since 45.0g of calcium carbonate are used, the produced moles of carbon dioxide, via stoichiometry, are found to be:
[tex]n_{CO_2}=45.0g CaCO_3*\frac{1molCaCO_3}{100gCaCO_3}*\frac{1molCO_2}{1molCaCO_3}=0.45molCO_2[/tex]
Finally, since STP conditions are referred to a temperature of 273.15K and 1 atm, the volume, by using the ideal gas equation result:
[tex]V=\frac{nRT}{P}=\frac{0.45mol*0.082\frac{atm*L}{mol*K}*273.15K }{1atm} \\ \\V=10.1L[/tex]
So the answer is B) 10.1 L.
Best regards.
Answer:
B. 10.1L
Explanation:
this is correct just did the worksheet with this on it.
