Answer:
7.888m
Explanation:
Given:
frequency 'f'= 90Hz
velocity of the sound 'v' = 340 m /sec
The wavelength of the wave is given by,
λ= v/f => 340/90
λ= 3.777m
The destructive interference condition is givn by
Δd= [tex](m+\frac{1}{2} )[/tex] λ
where, m=0,1,2,3,..
m=0, for minimum destructive interference
Δd= [tex](0+\frac{1}{2} )[/tex] x 3.777
Δd=1.888
Therefore, the required distance is
[tex]d_f[/tex]=[tex]d_i[/tex] + Δd => 6 + 1.888
[tex]d_f[/tex]= 7.888m
Thus, So the speaker should be placed at 7.888 m