A company produces batteries. On average,85% of all batteries produced are good. Each battery is tested before being dispatched, and the inspector correctly classifies the battery 90% of the time. A.What percentage of the batteries will be“classified as good”?B.What is the probability that a battery is defective given that it was classified as good?

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Answer:

a) 78% of the batteries will be classified as good.

b) 1.92% probability that a battery is defective given that it was classified as good

Step-by-step explanation:

A brief introduction about the conditional probability formula.

Conditional probability formula:

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]

In which

P(B|A) is the probability of event B happening, given that A happened.

[tex]P(A \cap B)[tex] is the probability of both A and B happening.

P(A) is the probability of A happening.

A.What percentage of the batteries will be“classified as good”?

85% are good, and of those, 90% are classified as good.

15% are not good and of those, 10% are classified as good.

Then

0.9*0.85 + 0.1*0.15 = 0.78

78% of the batteries will be classified as good.

B.What is the probability that a battery is defective given that it was classified as good?

Conditional probability.

A: Classified as good

B: Defective.

From a), P(A) = 0.78

Intersection:

Classified as good, but defective.

This is 10% of 15%.

[tex]P(A \cap B) = 0.1*0.15 = 0.015[/tex]

Then:

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.015}{0.78} = 0.0192[/tex]

1.92% probability that a battery is defective given that it was classified as good