Answer:
ΔT = 1628 K
Explanation:
Let '[tex]i_o[/tex]' be initial current
then, final current= i = [tex]i_o[/tex]/8
Let V represents potential difference.
coefficient of resistivity, α = 4.3 x [tex]10^-^3[/tex] /K
The resistance varies with temperature
R = Ro ( 1 + α ΔT)
where,
R is resistance and [tex]R_o[/tex] is the final resistance
V/i = V/ [tex]i_o[/tex](1 + α ΔT )
8 = 1 + (4.3 x [tex]10^-^3[/tex] x ΔT )
7 = 4.3 x [tex]10^-^3[/tex]x ΔT
ΔT = 1628 K
Therefore, the change in temperature of the filament is 1628 K