Respuesta :
Answer:
[tex] ME = t_{\alpha/2} \frac{s}{\sqrt{n}}[/tex]
And the width for the confidence interval is given by:
[tex]Width =2ME=2t_{\alpha/2} \frac{s}{\sqrt{n}}[/tex]
And we want to see the effect if we increase the confidence level for a interval. On this case if we increase the confidence level then the critical value for the confidence interval [tex]t_{\alpha/2}[/tex] would be higher and then the width of the interval would increase. So then the best answer for this case would be:
B. Increasing the level of confidence widens the interval.
Step-by-step explanation:
Let's assume that we have a parameter of interest [tex]\mu[/tex] who represent for example the true mean for a population. And we can construct a confidence interval in order to estimate this parameter if we know the distribution for the statistic let's say [tex]\bar X[/tex] and for this particular example the confidence interval is given by:
[tex] \bar X \pm ME[/tex]
Where ME represent the margin of error for the estimation and this margin of error is given by:
[tex] ME = t_{\alpha/2} \frac{s}{\sqrt{n}}[/tex]
And the width for the confidence interval is given by:
[tex]Width =2ME=2t_{\alpha/2} \frac{s}{\sqrt{n}}[/tex]
And we want to see the effect if we increase the confidence level for a interval. On this case if we increase the confidence level then the critical value for the confidence interval [tex]t_{\alpha/2}[/tex] would be higher and then the width of the interval would increase. So then the best answer for this case would be:
B. Increasing the level of confidence widens the interval.