Answer:
B. 2 m/s
B. Acceleration = 4.05 m/s² and Tension = 297.5 N.
Explanation:
A force is applied on a mass m whose acceleration is 4 m/s
Force = mass × acceleration
a = F/m = 4 m/s
4 m/s = F/m
F = 4 m/s (m)
If Force of 2F is applied on a mass of 4m ; it acceleration is as follows:
2F/4 m = F/ 2m
4m/s (m) / 2m = 2 m/s
a = 2 m/s
2.
Given that
mass [tex]m_1[/tex] = 30 kg
mass [tex]m_2[/tex] = 50 kg
[tex]\mu[/tex] = 0.1
From the question; we can arrive at two cases;
That :
[tex]m_{2} a _ \ {net} }= m_2g - T[/tex] ----- equation (1)
[tex]m_{1} a _ \ {net} }= T - mg sin \theta - F[/tex] ---- equation (2)
50 a = 50 g - T
30 a = T - 30 g sin 30 - 4 × 30 g cos 30
By summation
80 a =[tex][ 50 - 30 * \frac{1}{2} - 0.1 *30* \frac{\sqrt{3}}{2}][/tex]g
80 a = 32. 4 × 10 m/s ² (using g as 10m/s²)
80 a = 324 m/s ²
a = 324/80
a = 4.05 m/s²
From equation , replace a with 4.05
50 × 4.05 = 50 × 10 - T
T = 500 -202.5
T =297.5 N
