The variable a is the length of the ladder. The variable h is the height of the ladder’s top at time t, and x is the distance from the wall to the ladder’s bottom. Suppose that the length of the ladder is 6.7 meters and the top is sliding down the wall at a rate of 0.2m/s. What are the values of h and x at the moment when the top and bottom of the ladder move at the same speed? (Use decimal notation. Give your answer to three decimal places.)

Respuesta :

Answer:

x=4.738 meters

h=4.738 meters

Step-by-step explanation:

a = length of the ladder.

h = height of the ladder’s top at time t, and

x = distance from the wall to the ladder’s bottom.

From Pythagoras Theorem

[tex]a^2=x^2+h^2[/tex]

If a=6.7 meters, then:

[tex]6.7^2=x^2+h^2[/tex]

The top is sliding down the wall(decreasing) at a rate of 0.2m/s, therefore:

[tex]\frac{dh}{dt}=-0.2 m/s[/tex]

If the top and bottom of the ladder move at the same speed, then:

[tex]\frac{dx}{dt}=0.2 m/s[/tex]

Taking derivative of [tex]a^2=x^2+h^2[/tex]

[tex]2x\frac{dx}{dt}+2h\frac{dh}{dt}=0[/tex]

[tex]2x(0.2)+2h(-0.2)=0\\0.4x=0.4h\\x=h[/tex]

From [tex]6.7^2=x^2+h^2[/tex]

Since x=h

[tex]6.7^2=x^2+x^2\\2x^2=6.7^2\\x^2=44.89/2\\x=\sqrt{44.89/2} \\$x=4.738\:meters\\Therefore:\\h=4.738\:meters[/tex]