The original pressure in a rigid container if the new pressure is 82.5atm and the temperature was raised from 44°C to 67°C is 76.90atm
PRESSURE LAW:
- The original pressure of a container can be calculated using the pressure law formula as follows:
P1/T1 = P2/T2
Where;
- P1 = original pressure (atm)
- P2 = new pressure (atm)
- T1 = original temperature (K)
- T2 = new temperature (K)
- According to this question, the new pressure of the container is 82.5atm and the temperature was raised from 44°C to 67°C.
- T1 = 44°C + 273 = 317K
- T2 = 67°C + 273 = 340K
P1/317 = 82.5/340
P1/317 = 0.2426
P1 = 76.90atm
- Therefore, the original pressure in a rigid container if the new pressure is 82.5atm and the temperature was raised from 44°C to 67°C is 76.90atm.
Learn more at: https://brainly.com/question/24106768?referrer=searchResults
