Answer: [tex]6.023\times 10^{23}[/tex] molecules
Explanation:
According to ideal gas equation:
[tex]PV=nRT[/tex]
P = pressure of gas = 1 atm (at STP)
V = Volume of gas = 22.4 L
n = number of moles = ?
R = gas constant =[tex]0.0821Latm/Kmol[/tex]
T =temperature =[tex]273K[/tex] (at STP)
[tex]n=\frac{PV}{RT}[/tex]
[tex]n=\frac{1atm\times 22.4L}{0.0821L atm/K mol\times 273K}=1mole[/tex]
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.
1 mole of [tex]CH_4[/tex] contains [tex]6.023\times 10^{23}[/tex] molecules
