Respuesta :

Answer:

sqrt3[sqrt3+2sqrt12]=sqrt3[sqrt3+4sqrt3] = sqrt3[5sqrt3= 3x5 =15

Answer:

D

Step-by-step explanation:

Using the rule of radicals

[tex]\sqrt{a}[/tex] × [tex]\sqrt{b}[/tex] ⇔ [tex]\sqrt{ab}[/tex]

Given

[tex]\sqrt{3}[/tex] ([tex]\sqrt{3}[/tex] + 2[tex]\sqrt{12}[/tex] ) ← distribute

= 3 + 2[tex]\sqrt{36}[/tex]

= 3 + (2 × 6)

= 3 + 12

= 15 → D