Answer:
At 0.713 second the ball will hit the ground
Step-by-step explanation:
The height of an object t seconds after it is thrown from a height of h feet is modeled by the equation:
[tex]h(t) = -16t^2 + vt + h[/tex]
The ball is thrown from a point 6 feet above ground with an initial velocity, v, of 30 feet per second, equation becomes:
[tex]h(t) = -16t^2 + 3t + 6[/tex]
It is required to find the time when the ball hits the ground. At that point, h(t) =0.
So,
[tex]-16t^2 + 3t + 6=0[/tex]
Above is a quadratic equation, the value of time is given by :
t = -0.526 s and t = 0.713 seconds
So, at 0.713 second the ball will hit the ground.
