Answer : The correct option is (d) 14.6 %
Explanation :
Percent composition : It is calculated by dividing the mass of each element in one mole of the compound that means dividing the mass of each element by the total molar mass of the compound.
Formula used :
[tex]\%\text{ Composition of phosphorus}=\frac{\text{Mass of phosphorus element}}{\text{Molar mass of compound}}\times 100[/tex]
Molar mass of compound, [tex]Be_3(PO_4)_2[/tex] = 216.9 g/mol
Molar mass of phosphorus = 30.9 g/mol
[tex]\%\text{ Composition of phosphorus}=\frac{31g/mol}{217g/mol}\times 100[/tex]
[tex]\%\text{ Composition of phosphorus}=14.6\%[/tex]
Therefore, the percent composition of phosphorus in [tex]Be_3(PO_4)_2[/tex] is 14.6 %.
