Answer:
[H+] = 5.01x10^–13
Explanation:
To answer the question, let us obtain:
1. The hydrogen ion concentration, [H+] of the Liquid drano.
This is illustrated below:
pH = 12.3
hydrogen ion concentration, [H+] =?
pH = –Log [H+]
12.3 = –Log [H+]
–12.3 = Log [H+]
[H+] = Anti log (–12.3)
[H+] = 5.01x10^–13
2. The pOH of the Liquid drano.
pH + pOH = 14
pH = 12.3
12.3 + pOH = 14
Collect like terms
pOH = 14 – 12.3
pOH = 1.7
3. The hydroxide ion concentration, [OH-] of Liquid drano.
pOH = –Log [OH-]
pOH = 1.7
1.7 = –Log [OH-]
–1.7 = –Log [OH-]
[OH-] = Anti log (–1.7 )
[OH-] = 2.0x10^–2
Now, considering the options given in the question, the right answer is
[H+] = 5.01x10^–13
