Answer:
101 i hope this helps
Step-by-step explanation:
Given: A standard octagon has a span of 6 ft and a side length of 4.6 ft.
To discover the territory of a normal octagon(A) of side length an is given by :
[tex]A=2*(1+\sqrt{2})a^{2}[/tex]
Given the length of side, a= 4.6 ft
Substitute the estimation of a=4.6 ft in the given equation of zone:
[tex]A=2*(1+\sqrt{2} )*(4.5)^{2}[/tex]
or then again
[tex]A=(2+2\sqrt{2} )*(21.16)[/tex]
or then again
[tex]A=(2+2.828) *(21.16)[/tex]
Streamline:
[tex]A=4.828*21.16=102.16048 ft^{2}[/tex]
along these lines, the inexact zone of ordinary octagon is, 101 square ft
