contestada

How much heat is released from burning 42.6 grams of CH4?

CH4 (g) + 2 O2 (g) ---> CO2 (g) + 2 H2O (l) delta H = -890.4 kJ

Respuesta :

Answer:

-2.37 × 10³ kJ

Explanation:

Let's consider the following thermochemical equation.

CH₄(g) + 2 O₂(g) ⇒ CO₂(g) + 2 H₂O(l)    ΔH = -890.4 kJ

Step 1: Calculate the moles corresponding to 42.6 g of methane

The molar mass of CH₄ is 16.04 g/mol. We will use this to calculate the moles corresponding to 42.6 g of CH₄.

[tex]42.6g \times \frac{1mol}{16.04g} = 2.66mol[/tex]

Step 2: Calculate the heat released from burning 2.66 moles of methane

According to the thermochemical equation, 890.4 kJ are released from burning 1 mol of methane. Then,

[tex]\frac{-890.4kJ}{1molCH_4} \times 2.66molCH_4 = -2.37 \times 10^{3} kJ[/tex]