Answer : The molarity of [tex]KF[/tex] in the solution is 1.5 M.
Explanation : Given,
Moles of [tex]KF[/tex] = 3.0 mol
Volume of solution = 2.00 L
Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.
Formula used :
[tex]\text{Molarity}=\frac{\text{Moles of }KF}{\text{Volume of solution (in L)}}[/tex]
Now put all the given values in this formula, we get:
[tex]\text{Molarity}=\frac{3.0mol}{2.00L}=1.5mole/L=1.5M[/tex]
Therefore, the molarity of [tex]KF[/tex] in the solution is 1.5 M.
