samanthamurphy22
contestada

Based on the following equation, how many moles of each product are produced when 8.9 moles of Zn (OH) 2 are reacted with H3PO4? (mole-to-mole conversion) 3 Zn (OH) 2 + 2 H; PO4 - Zn3 (PO4) 2 + 6 H2O

Respuesta :

pstnonsonjoku

Answer:

2.97 moles of Zinc II phosphate

17.8 moles of water

Explanation:

The balanced reaction equation is ;

3Zn(OH)2(aq) + 2H3PO4(aq) -----> Zn3(PO4)2(aq) + 6H2O(l)

The two reaction products are zinc II phosphate and water.

Let us begin with zinc II phosphate.

3 moles of Zinc II hydroxide yields 1 mole zinc II phosphate

8.9 moles of Zinc II hydroxide will yield 8.9 × 1 /3 = 2.97 moles of Zinc II phosphate

For water

3 moles of zinc II hydroxide yields 6 moles of water

8.9 moles of Zinc II hydroxide will yield 8.9 × 6/3 = 17.8 moles of water

Otras preguntas