Answer: [tex]\frac{(x-2)^2}{25} +\frac{(y-3)^2}{36} =1[/tex]
Step-by-step explanation:
We know the ellipse is centered at (2,3) therefore in our function,
[tex]\frac{(x-h)^2}{a^2} +\frac{(y-k)^2}{b^2} =1[/tex]
h = 2 and k = 3
[tex]\frac{(x-2)^2}{a^3} +\frac{(y-3)^2}{b^2} =1[/tex]
We know the 'a' value will be on the right because there is a horizontal minor axis.
