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sebassandin

Answer:

[tex]M_{HCl}=0.390M[/tex]

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

[tex]HCl+NaOH\rightarrow NaCl+H_2O[/tex]

In such a way, for the neutralization, the moles of sodium hydroxide must equal those of the hydrochloric acid considering their 1:1 molar ratio in the chemical reaction:

[tex]n_{HCl}=n_{NaOH}[/tex]

Hence, in terms of molarities and volumes:

[tex]M_{NaOH}V_{NaOH}=M_{HCl}V_{HCl}[/tex]

Thus, solving for the molarity of the hydrochloric acid solution we obtain:

[tex]M_{HCl}=\frac{M_{NaOH}V_{NaOH}}{V_{HCl}}=\frac{0.212M*25.0mL}{13.6mL}\\ \\M_{HCl}=0.390M[/tex]

Best regards.

Cricetus

The molarity of the HCl solution will be "0.390 M".

According to the question,

  • [tex]M_{NaOH} = 0.212 \ M[/tex]
  • [tex]V_{NaOH} = 25.0 \ mL[/tex]
  • [tex]V_{HCl} = 13.6 \ mL[/tex]

The chemical reaction will be:

  • [tex]HCl+NaOH \rightarrow NaCl+NH_2O[/tex]

The relation:

→ [tex]M_{NaOH} V_{NaOH} = M_{HCl} V_{HCl}[/tex]

or,

→ [tex]M_{HCl} = \frac{M_{NaOH}V_{NaOH}}{V_{HCl}}[/tex]

By substituting the values, we get

             [tex]= \frac{0.212\times 25.0}{13.6}[/tex]

             [tex]= 0.390 \ M[/tex]

Thus the above approach is correct.

Learn more about molarity here:

https://brainly.com/question/12773321

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