Answer: 15.0 moles of [tex](NH_4)_2SO_4[/tex] are formed from 30.0 mol of [tex]NH_3[/tex]
Explanation:
The balanced chemical reaction is :
[tex]2NH_3+H_2SO_4\rightarrow (NH_4)_2SO_4[/tex]
According to stoichiometry :
2 moles of [tex]NH_3[/tex] give = 1 mole of [tex](NH_4)_2SO_4[/tex]
Thus 30.0 moles of [tex]NH_3[/tex] will give =[tex]\frac{1}{2}\times 30.0=15.0moles[/tex] of [tex](NH_4)_2SO_4[/tex]
Thus 15.0 moles of [tex](NH_4)_2SO_4[/tex] are formed from 30.0 mol of [tex]NH_3[/tex]
