bell1060
bell1060 bell1060
  • 13-05-2020
  • Mathematics
contestada

Find three consecutive interferes whose sum is 96

Respuesta :

hannah818lucas hannah818lucas
  • 13-05-2020

Answer:

31, 32, 33

Step-by-step explanation:

x + x + 1 +x + 2 = 96

3x + 3 = 96

      -3    -3

3x = 93

/3     /3

x = 31

31 is the first number, so since they’re consecutive, the second two numbers are 32 and 33.

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