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What is the temperature of 0.750 mol of a gas stored in a 6,850 mL cylinder at 2.21 atm?
Use PV = nRT and R-0.0821 Leatm
molok:
2.95 K
5.24 K
138 K
246 K

Respuesta :

Answer:

246 K

Explanation:

6.850 mL=6.85 L

PV=nRT

T=PV/nR

T= (2.21 atm* 6.85  L)/(0.750 mol * 0.0821)

T=246 K
It’s 24k! That’s the answer