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A 3 kg bowling ball is thrown onto a mattress. If it takes 0.3 seconds to stop the ball using a force of 24 N, what was the initial velocity of the bowling ball when it first touched the mattress?

Respuesta :

ajeigbeibraheem

Answer:

-24 m/s

Explanation:

mass of the bowling ball =  3 kg

time (t) = 0.3 seconds

Force = 24 N

initial velocity u = ???

We know that;

Force = mass × acceleration (a)

So;

24 = 3 × a

a = 24/3

a = 8 m/s²

Also;

From equation of motion; acceleration is given by the relation;

[tex]a =\frac{v-u}{t}[/tex]

if v = 0

then ;

[tex]8 = \frac{0-u}{0.3}[/tex]

24 = 0- u

u = -24 m/s

Thus; the  initial velocity of the bowling ball when it first touched the mattress =  -24 m/s

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