Respuesta :
Answer:
The correct option is;
A.) 15 g to 18 g
Explanation:
The solubility of sulfur dioxide at room temperature = 94 g/L of water forming sulfurous acid as follows;
SO₂ + H₂O ⇄ HSO₃⁻ + H⁺
Which is a partial reversibly association with water molecules
Whereby 1 liter of water weighs 1 kg
9.4 gram of SO₂ will dissolve in 100 g of water at room temperature of 23 to 24°C
The solubility increases as the temperature reduces therefore as shown from the sulfur dioxide solubility chart we have;
At 10°C the solubility of SO₂ (g) is midway between 150 g to 200 g per kg of water
Therefore;
The solubility of SO₂ (g) is between 15 g to 18 g per 100 of water.
The mass of SO2 in the given solution should be an option a 15g to 18g.
Calculation of the mass:
Since the solubility of sulfur dioxide at room temperature = 94 g/L of water forming sulfurous acid likewise:
SO₂ + H₂O ⇄ HSO₃⁻ + H⁺
This represents the partial reversibly association along with water molecules
Here 1 liter of water weighs 1 kg
So we can say that
9.4 gram of SO₂ will dissolve in 100 g of water at room temperature of 23 to 24°C
Due to this, there is an increase in solubility this result in decrease in the temperature
Also, At 10°C the solubility of SO₂ (g) is midway between 150 g to 200 g per kg of water
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