What is the equation of the line that is parallel to the given
line and passes through the point (-3, 2)?
3x - 4y = -17
O 3x - 4y = -20
4x + 3y = -2
O 4x + 3y = -6

Respuesta :

Answer:

Step-by-step explanation:

is the given line  3x - 4y = -17?

then,

- 4y = -3x -17

y=(3/4)x+17/4

it is parallel, so slope of our line is 3/4 or 0.75

y=0.75x+b

next, lets plug in the given point to get the y-int

2=0.75*(-3)+b

2=-2.25+b

b-2.25=2

b=4.25

the equation is y=0.75x+4.25

does this clear anything, or am I off topic? please tell me I will help you

The equation of line is [tex]y=\frac{3}{4}x+\frac{17}{4}[/tex]

Slope-intercept form of line :

The given equation of line is,

                            [tex]3x-4y=-17\\\\4y=3x+17\\\\y=\frac{3}{4} x+\frac{17}{4}[/tex]

Compare above equation with [tex]y=mx+c[/tex]

Slope of given line [tex]m=\frac{3}{4}[/tex]

Since, the slope of all parallel lines are same.

So that, slope of required line is also [tex]\frac{3}{4}[/tex]

The equation of line is, [tex]y=\frac{3}{4}x+c\\[/tex]

Substitute point [tex](-3,2)[/tex] in above equation.

                   [tex]2=\frac{3}{4}(-3)+c\\\\\\c=2+\frac{9}{4} =\frac{17}{4}[/tex]

Substitute  value of c in equation of line.

       [tex]y=\frac{3}{4}x+\frac{17}{4} \\\\\\[/tex]

Thus, the equation of line is [tex]y=\frac{3}{4}x+\frac{17}{4}[/tex]

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