Respuesta :
Answer:
Replace /* Your solution goes here */ with the following lines of code
for(i = 0;i<SCORES_SIZE-1;i++)
{
bonusScores[i]+=bonusScores[i+1];
}
Explanation:
The above iteration starts from the index element (element at 0) and stops at the second to the last element (last - 1).
Using an iterative variable, i
It adds the current element (element at i) with the next element; element at i + 1.
The full code becomes
#include<iostream>
using namespace std;
int main(void) {
const int SCORES_SIZE = 4;
int bonusScores[SCORES_SIZE];
int i = 0;
bonusScores[0] = 10;
bonusScores[1] = 20;
bonusScores[2] = 30;
bonusScores[3] = 40;
for(i = 0;i<SCORES_SIZE-1;i++)
{
bonusScores[i]+=bonusScores[i+1];
}
/* Your solution goes here */
for (i = 0; i < SCORES_SIZE; ++i) {
printf("%d ", bonusScores[i]);
}
printf("\n");
return 0;
}
See attachment for .cpp file
Answer:int main() {
const int SCORES_SIZE = 4;
int bonusScores[SCORES_SIZE];
int i;
for (i = 0; i < SCORES_SIZE; ++i) {
cin >> bonusScores[i];
}
for (i = 0; i < SCORES_SIZE-1; ++i){
bonusScores[i] += bonusScores[i+1];
}
for (i = 0; i < SCORES_SIZE; ++i) {
cout << bonusScores[i] << " ";
}
cout << endl;
return 0;
}
Explanation: SCORES_SIZE -1 will prevent the for loop from going past the last value in the array. bonusScores[i] += will add the value of bonusScores[i+1] to the original bonusScores[i].
for example, i = 1; 1 < SCORES_SIZE - 1 ; bonusScores[1] += bonusScores[1+1} becomes{ bonusScores[1] + bonusScores{2];