aubreykeyonnie15 aubreykeyonnie15

10-06-2020
Mathematics

contestada

Solve for n.
n + 1 = 4(n-3)
O n = 1
n = 8
On = 11
On = 16

Respuesta :

manu279965 manu279965

10-06-2020

n + 1 = 4n - 3
-4n -4n

-3n + 1 = -3
-1 -1

-3n -4
-3 -3

n= 1.33

Answer Link

bbyreirei bbyreirei

10-06-2020

n+1=4(n+3)
n+1(4)(n)+(4)(3)
n+1=4n+12
n+1-4n=4n+12-4n
-3n+1=12
-3n+1-1=12-1
-3n=11
-3n/-3=11/-3
n=-11/3

Answer Link

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