Answer:
Step-by-step explanation:
[tex](\frac{5}{7}-4)2+3+11=(\frac{5}{7}-\frac{4*7}{7})2+3+11\\\\=(\frac{5}{7}-\frac{28}{7})2+3+11\\\\=(\frac{-23}{7})2+3+11\\\\=\frac{-46}{7}+3+11\\\\=\frac{-46}{7}+14\\\\=\frac{-46}{7}+\frac{14*7}{1*7}\\\\=\frac{-46}{7}+\frac{98}{7}\\\\=\frac{-46+98}{7}\\\\=\frac{52}{7}\\\\=7\frac{3}{7}[/tex]
