Answer:
y = - [tex]\frac{4}{5}[/tex] x + [tex]\frac{2}{5}[/tex]
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Rearrange 4y = 5x + 3 into this form by dividing the 3 terms by 4
y = [tex]\frac{5}{4}[/tex] x + [tex]\frac{3}{4}[/tex] ← in slope- intercept form
with slope m = [tex]\frac{5}{4}[/tex]
Given a line with slope m then the slope of a line perpendicular to it is
[tex]m_{perpendicular}[/tex] = - [tex]\frac{1}{m}[/tex] = - [tex]\frac{1}{\frac{5}{4} }[/tex] = - [tex]\frac{4}{5}[/tex] , thus
y = - [tex]\frac{4}{5}[/tex] x + c ← is the partial equation
To find c substitute (3, - 2) into the partial equation
- 2 = - [tex]\frac{12}{5}[/tex] + c ⇒ c = - 2 + [tex]\frac{12}{5}[/tex] = [tex]\frac{2}{5}[/tex]
y = - [tex]\frac{4}{5}[/tex] x + [tex]\frac{2}{5}[/tex] ← equation of perpendicular line