Respuesta :
Answer:
b
Step-by-step explanation:
given
6x² + 17x + 5
Consider the factors of the product of the x² term and the constant term which sum to give the coefficient of the x- term
product = 6 × 5 = 30 and sum = 17
The factors are 2 and 15
Use these factors to split the x- term
6x² + 2x + 15x + 5 ( factor the first/second and third/fourth terms )
= 2x(3x + 1) + 5(3x + 1) ← factor out (3x + 1) from each term
= (3x + 1)(2x + 5) → b
The two steps are [tex]3x(2x+5)+1(2x+5)[/tex] and [tex](3x+1)(2x+5)[/tex]. So, options b and d are correct.
Important information:
- The given trinomial is [tex]6x^2+17x+5[/tex].
Factoring:
Splitting the middle term, we get
[tex]6x^2+15x+2x+5[/tex]
After grouping, we get
[tex](6x^2+15x)+(2x+5)[/tex]
Taking out common factors, we get
[tex]3x(2x+5)+1(2x+5)[/tex]
Now, it can be written as:
[tex](3x+1)(2x+5)[/tex]
Therefore, the correct options are b and d.
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