Answer:
A (-2, 10)
Step-by-step explanation:
If you plug in the point into x and y you should get "false" on a calculator, or the answer won't make sense, meaning that it's not a part of the set
(-2,10) is not the solution set of the given equation [tex]3y+2 =x^{2} -5x+17[/tex].
The solution, or root, of an equation is any value or set of values that can be substituted into the equation to make it a true statement.
According to the given question
We have an equation
[tex]3y + 2 =x^{2} -5x+17[/tex]
The above equation can be written as
[tex]x^{2} -5x +17-3y-2=0...(i)[/tex]
For finding the point which is not the solution set of the equation, first we will substitute the given points in the above equation and check whether it making the equation true or not.
For point (-2, 10)
Substitute, x = -2 and y = 10 in the equation (i)
[tex](-2)^{2} -5(-2) + 17 - 3(10) -2\\=4+10+17-30-2\\= -1\neq 0[/tex]
Hence, (-2, 10) is not the solution of the given equation.
For point (5, 5)
Substitute, x = 5, and y = 5 in equation (i)
[tex](5)^{2} -5(5)+17-3(5)-2\\=25-25+17-15-2\\=0[/tex]
Hence, (5, 5) is the solution of the given equation.
Learn more about solution to the equation here:
https://brainly.com/question/545403
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