In ΔIJK, the measure of ∠K=90°, KI = 5.3 feet, and JK = 2.1 feet. Find the measure of ∠I to the nearest tenth of a degree. I

Respuesta :

Answer:

[tex]\angle I = 21.6 ^\circ[/tex] is the correct answer.

Step-by-step explanation:

Please refer to the attached figure.

[tex]\triangle IJK[/tex] is shown with the following measurements:

[tex]\angle K = 90^\circ[/tex]

Side KI = 5.3 ft

Side JK = 2.1 ft

To find : [tex]\angle I[/tex] = ?

Using trigonometric identity for tangent of an angle:

[tex]tan\theta = \dfrac{\text{Perpendicular}}{\text{Base}}[/tex]

Here [tex]\theta = \angle I[/tex]

Perpendicular is side JK.

Base is side KI.

Putting the values in above formula:

[tex]tan\theta = \dfrac{\text{JK}}{\text{KI}}\\\Rightarrow tan\theta = \dfrac{2.1}{5.3}\\\Rightarrow tan\theta = 0.3962\\\Rightarrow \theta = 21.6^\circ[/tex]

Hence, [tex]\angle I = 21.6 ^\circ[/tex] is the correct answer.