Three spinners numbered 1 through 12 are spun. What is the probability of spinning a five on the first spinner, an even number on the second spinner, and a multiple of 4 on the third spinner?

1/96
1/72
7/12
5/6

Respuesta :

Answer:

[tex]\frac{1}{96}[/tex]

Step-by-step explanation:

Spinning a 5 is [tex]\frac{1}{12}[/tex]

Spinning even is [tex]\frac{1}{2}[/tex]

Spinning multiple of 4 is [tex]\frac{1}{4}[/tex]

[tex]\frac{1}{12} *\frac{1}{2} *\frac{1}{4}[/tex][tex]=\frac{1}{96}[/tex]