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What is the product?

(6 r minus 1)(negative 8 r minus 3)

negative 48 r squared minus 10 r + 3
negative 48 r squared minus 10 r minus 3
negative 48 r squared + 3
negative 48 r squared minus 3

Respuesta :

CHERLYNnotCHERRY

Answer:

The answer is option 1.

Step-by-step explanation:

You have to use Distributive Laws,

[tex]a(b + c) = ab + ac[/tex]

So for this question :

[tex](6r - 1)( - 8r - 3)[/tex]

[tex] = 6r( - 8r) + 6r( - 3) - 1( - 8r) - 1( - 3)[/tex]

[tex] = - 48 {r}^{2} - 18r + 8r + 3[/tex]

[tex] = - 48 {r}^{2} - 10r + 3[/tex]

samueladesida43

The product of the expression is (6r - 1) (-8r - 3) is negative 48 r squared minus 10 r + 3.

What is an algebraic expression?

Algebraic expression is a mathematical equation in which one or both sides is an algebraic expression, such as 2x + 7y = 3.

According to this question, the following expression is given:

(6r - 1) (-8r - 3)

  • 6r × -8r = -48r²
  • - 1 × -8r = 8r
  • 6r × -3 = -18r
  • -1 × -3 = 3

Therefore, the product of the expression is -48r² -10r + 3

Learn more about algebra at: https://brainly.com/question/953809

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