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2Objects 1 and 2 attract each other with a electrostatic force of 18.0 units. If the charge of Object 1 is one-fourth the original value AND the charge of object 2 is tripled AND the distance separating Objects 1 and 2 is halved, then the new electrostatic force will be _____ units.

Respuesta :

Answer:

The new force becomes 3 times of the initial force.

Explanation:

Let q₁ and q₂ are two charged particles. The force between them is given by :

[tex]F=\dfrac{kq_1q_2}{r^2}\ ......(1)[/tex]

If [tex]q_1'=\dfrac{q_1}{4}[/tex]

and

[tex]q_2'=3q_2[/tex]

Also, r' = r/2

New force,

[tex]F'=\dfrac{kq_1'q_2'}{r'^2}[/tex]

Putting all the above values,

[tex]F'=\dfrac{k\dfrac{q_1}{4}3q_2}{(r/2)^2}\\\\F'=3\times \dfrac{kq_1q_2}{r^2}\\\\F'=3F[/tex]

So, the new force becomes 3 times of the initial force.

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