Respuesta :
Answer:
[tex]\left ( \frac{3x_2+5x_1}{8},\frac{3y_2+5y_1}{8} \right )[/tex]
Step-by-step explanation:
Given: P is Three-fifths the length of the line segment from K to J
To find: x- and y-coordinates of point P on the directed line segment from K to J
Solution:
Section formula:
Let point K and J be [tex](x_1,y_1)\,,\,(x_2,y_2)[/tex] such that the point [tex]p(x,y)[/tex] divides KJ in ratio [tex]m:n[/tex]
Then coordinates of point P are given by [tex]\left ( \frac{mx_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n} \right )[/tex]
Take [tex]m:n=3:5[/tex]
So,
coordinates of point P = [tex]\left ( \frac{3x_2+5x_1}{3+5},\frac{3y_2+5y_1}{3+5} \right )=\left ( \frac{3x_2+5x_1}{8},\frac{3y_2+5y_1}{8} \right )[/tex]
