The temperature changes for the water and the metal is
ΔT (water) = 4.7°C
ΔT (metal) = - 72.9°C
Specific Heat
The quantity or amount of heat per unit mass required to raise the temperature of a body by one degree Celsius is known as specific heat. The unit of specific heat are joules or calories per gram per degree Celsius. Specific heat is an intensive property.
Calculate the temperature changes
Relationship between temperature and heat is expressed as:
Q = mcΔT
where,
Q is heat energy in Joules (J)
m is mass (in grams)
c is specific heat in J/g°C
ΔT is change in temperature
Now calculate the temperature changes for the water
ΔT (water) = T(final) - T(initial)
= 27.1 - 22.4
= 4.7°C
Now calculate the temperature changes for the metal
ΔT(metal) = T(final) - T(initial)
= 27.1 - 100
= -72.9°C
Thus, from the above calculation we can see that the temperature changes for the water and the metal is
ΔT (water) = 4.7°C
ΔT (metal) = - 72.9°C
Learn more about the specific heat here: https://brainly.com/question/21406849
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